Author Topic: Calculating Losses to hoses  (Read 2292 times)

Offline blatz

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Calculating Losses to hoses
« on: January 16, 2013, 08:31:56 AM »
How much wort am I losing to 30' of 1/2" ID tubing?
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Online morticaixavier

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Re: Calculating Losses to hoses
« Reply #1 on: January 16, 2013, 08:44:06 AM »
~182322 cubic millimeters worth  ;D
which is about 182 ml

If my math is right which I am not 100% sure about.
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Offline hokerer

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Re: Calculating Losses to hoses
« Reply #2 on: January 16, 2013, 08:46:46 AM »
How much wort am I losing to 30' of 1/2" ID tubing?

Well, 30' of 1/2" tubing is a volume of about 70 cubic inches which would be about 1.22 quarts
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Re: Calculating Losses to hoses
« Reply #3 on: January 16, 2013, 08:49:44 AM »
How much wort am I losing to 30' of 1/2" ID tubing?

Well, 30' of 1/2" tubing is a volume of about 70 cubic inches which would be about 1.22 quarts

see I told you my math wasn't right.

His is  ;D
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Offline rjharper

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Re: Calculating Losses to hoses
« Reply #4 on: January 16, 2013, 08:50:25 AM »
I calculate (1/2" x 1/2" x PI)/4 x (30' x 12"/1') which gives a volume of 70.7 cubic inches which i about 1.22 quarts, or 1147 ccs.

Offline hokerer

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Re: Calculating Losses to hoses
« Reply #5 on: January 16, 2013, 08:52:17 AM »

see I told you my math wasn't right.

His is  ;D

That's what you get for trying to go metric :)
Joe

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Re: Calculating Losses to hoses
« Reply #6 on: January 16, 2013, 08:53:22 AM »

see I told you my math wasn't right.

His is  ;D

That's what you get for trying to go metric :)

yup, dropped a decimal place somewhere along the way.
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Offline brewmanator

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Re: Calculating Losses to hoses
« Reply #7 on: January 16, 2013, 08:55:47 AM »
I calculate (1/2" x 1/2" x PI)/4 x (30' x 12"/1') which gives a volume of 70.7 cubic inches which i about 1.22 quarts, or 1147 ccs.

That is more like what I calculated.  70.7 cubic inches is also around 2 imperial pints ;D
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Offline blatz

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Re: Calculating Losses to hoses
« Reply #8 on: January 16, 2013, 09:18:40 AM »
thanks guys!
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Offline redbeerman

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Re: Calculating Losses to hoses
« Reply #9 on: January 16, 2013, 09:41:41 AM »
Volume of a cylinder = Pi*r^2*h = Pi*.25^2*360 = 70.7 in^3 = 1.2 quarts yep
« Last Edit: January 16, 2013, 09:43:49 AM by redbeerman »
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Offline ibru

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Re: Calculating Losses to hoses
« Reply #10 on: January 16, 2013, 10:23:21 AM »
Can't you drain the hose into a sanitized beer pitcher then dump into the fermenter? Hate to waste 2 plus pints of potentially good beer!

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Offline blatz

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Re: Calculating Losses to hoses
« Reply #11 on: January 16, 2013, 10:29:29 AM »
Can't you drain the hose into a sanitized beer pitcher then dump into the fermenter? Hate to waste 2 plus pints of potentially good beer!

Bruce

not with my system - and most of that 'hose' is 2 CFCs back to back.  not to worry, I brew 12gal to make up all the losses...
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Offline narvin

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Re: Calculating Losses to hoses
« Reply #12 on: January 16, 2013, 10:34:10 AM »
Google conversions are really helpful:

(pi * (0.25 inches) ^2) * (30*12 inches) in quarts


Also, your pump should keep prime until the head is empty, so you'll only have losses in tubing after the pump.  Or you could get a peristaltic pump and have no losses ;-)
« Last Edit: January 16, 2013, 12:38:07 PM by narvin »
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Offline dean_palmer

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Re: Calculating Losses to hoses
« Reply #13 on: January 16, 2013, 12:01:20 PM »
I have two plate chillers back to back and was considering forcing out the last of the wort with oxygen. The same oxygen I use with an inline stone mounted in a tri-clamp, but then connected to the hose that came from the kettle to force all possible wort out of the system. At least it would be sanitary as opposed to using compressed air. I'll try it this weekend.

I'm also brewing extra to compensate, and it's about 1/4 gallon lost in my case.

Offline a10t2

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Re: Calculating Losses to hoses
« Reply #14 on: January 16, 2013, 12:33:04 PM »
You can just push it out with water, as long as you're using clear tubing or a sight glass.
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