# Line slope calculator 3x-y=19

**Straight line given by points A[7; 2] and B[8; 5]**

## Calculation:

**Slope-intercept form of line:**y = 3x-19

**Canonical form of the line equation:**3x-y-19 = 0

**Parametric form of the line equation:**

x = t+7

y = 3t+2 ; t ∈ R

**Slope:**m = 3

**Slope angle of line: φ =**71°33'54″ = 1.249 rad

**X intercept:**x

_{0}= 6.3333

**Y intercept:**y

_{0}= q = -19

**Distance line from the origin:**d

_{0}= 6.0083

**The length of the segment AB: |AB| =**3.1623

**Vector: AB =**(1; 3)

**Normal vector: n =**(3; -1)

**Midpoint of the segment AB: M =**[7.5; 3.5]

**Perpendicular Bisector equation:**x+3y-18 = 0

**Vector OA = (7; 2) ; |OA| = 7.2801**

**Vector OB = (8; 5) ; |OB| = 9.434**

**Scalar product OA .OB = 66**

**Angle ∠ AOB = 16°3'36″ = 0.2803 rad**