# Line slope calculator 5x-4y=18

**Straight line given by points A[6; 3] and B[10; 8]**

## Calculation:

**Slope-intercept form of line:**y = 1.25x-4.5

**Canonical form of the line equation:**5x-4y-18 = 0

**Parametric form of the line equation:**

x = 4t+6

y = 5t+3 ; t ∈ R

**Slope:**m = 1.25

**Slope angle of line: φ =**51°20'25″ = 0.8961 rad

**X intercept:**x

_{0}= 3.6

**Y intercept:**y

_{0}= q = -4.5

**Distance line from the origin:**d

_{0}= 2.8111

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; 5)

**Normal vector: n =**(5; -4)

**Midpoint of the segment AB: M =**[8; 5.5]

**Perpendicular Bisector equation:**4x+5y-59.5 = 0

**Vector OA = (6; 3) ; |OA| = 6.7082**

**Vector OB = (10; 8) ; |OB| = 12.8062**

**Scalar product OA .OB = 84**

**Angle ∠ AOB = 12°5'41″ = 0.2111 rad**