# Line slope calculator 5x+6y=50

**Straight line given by points A[4; 5] and B[10; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.8333x+8.3333

**Canonical form of the line equation:**5x+6y-50 = 0

**Parametric form of the line equation:**

x = 6t+4

y = -5t+5 ; t ∈ R

**Slope:**m = -0.8333

**Slope angle of line: φ =**-39°48'20″ = -0.6947 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 8.3333

**Distance line from the origin:**d

_{0}= 6.4018

**The length of the segment AB: |AB| =**7.8102

**Vector: AB =**(6; -5)

**Normal vector: n =**(5; 6)

**Midpoint of the segment AB: M =**[7; 2.5]

**Perpendicular Bisector equation:**6x-5y-29.5 = 0

**Vector OA = (4; 5) ; |OA| = 6.4031**

**Vector OB = (10; 0) ; |OB| = 10**

**Scalar product OA .OB = 40**

**Angle ∠ AOB = 51°20'25″ = 0.8961 rad**